The coordination number of Th in K4[Th(C2O4]4(OH2)2] is :- ( C2 O2-4 = Oxalato)

Question

The coordination number of Th in K4[Th(C2O4]4(OH2)2] is :- ( C2 O2-4 = Oxalato) (A) 6 (B) 10 (C) 14 (D) 8

Tardigrade Admin · Accepted Answer

C2O2-4 (oxalato): bidentate H2O (aqua): Monodentate

Q. The coordination number of Th in $K_{4} [T h (C_{2} O_{4}]_{4} (O H_{2})_{2}]$ is :-
$(C_{2} O_{4}^{2 -} =$ Oxalato)