Let AD be the perpendicular and D be the foot of the perpendicular which divides BC in the ratio λ:1, then D(λ+110λ−9,λ+14,λ+1−λ+5)…(i)
The direction ratios of AD are λ+110λ−9,λ+14 and λ+1−λ+5
and direction ratios of BC are 1 9 ,-4 and - 6
Since AD⊥BC, we get 19(λ+110λ−9)−4(λ+14)−6(λ+1−λ+5)=0
or λ=2831
Hence, on putting the value of λ in (i), we get required foot of the perpendicular, i.e., (5958,59112,59109)