The coordinates of a point are (0,1) and the ordinate of another point is -3. If the distance between the two point is 5 then the abscissa of another point is-

Question

The coordinates of a point are (0,1) and the ordinate of another point is -3. If the distance between the two point is 5 then the abscissa of another point is- (A) -3 (B) 3 (C) ± 3 (D) 1

Tardigrade Admin · Accepted Answer

The points are (0,1) and (x,-3) Distance between them =5 √x2+42=5 x=± 3

Q. The coordinates of a point are $(0, 1)$ and the ordinate of another point is $- 3$ . If the distance between the two point is 5 then the abscissa of another point is-

$- 3$

3

$\pm 3$

1

The points are $(0, 1)$ and $(x, - 3)$ Distance between them $= 5$
$x^{2} + 4^{2} = 5$
$x = \pm 3$

Q. The coordinates of a point are (0,1) and the ordinate of another point is −3. If the distance between the two point is 5 then the abscissa of another point is-

−3

3

±3

1

The points are (0,1) and (x,−3) Distance between them =5 x2+42​=5 x=±3

Q. The coordinates of a point are $(0, 1)$ and the ordinate of another point is $- 3$ . If the distance between the two point is 5 then the abscissa of another point is-

$- 3$

$\pm 3$

The points are $(0, 1)$ and $(x, - 3)$ Distance between them $= 5$
$x^{2} + 4^{2} = 5$
$x = \pm 3$