Question

The conjugate base of $N{H}_3$ is

• A. $N{H}_4^{+}$
• B. $N{H}_{4}OH$
• C. $N{H}_{2}OH$
• D. $N{H}_2^{-}$

Answer 1

Answer: (D)

A conjugate base has one proton less from the acid. If we remove one proton from $N{H}_3$, we get $N{H}_2^{-}.N{H}_3\to N{H}_2{}^{-}+H^{+}.$