The conductivities at infinite dilution of NH 4 Cl , NaOH and NaCl are 130,218,120 ohm -1 cm 2 eq -1 . If equivalent conductance of ( N /100) solution of NH 4 OH is 10 , then degree of dissociation of NH 4 OH at this dilution is

Question

The conductivities at infinite dilution of NH 4 Cl , NaOH and NaCl are 130,218,120 ohm -1 cm 2 eq -1 . If equivalent conductance of ( N /100) solution of NH 4 OH is 10 , then degree of dissociation of NH 4 OH at this dilution is (A) 0.005 (B) 0.043 (C) 0.01 (D) 0.02

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/98397b51ad8e41caa97118cd16f3c3a0-.png" /> 130+218=120+x α=(∧ m C /∧ m ∞)=(10/228)=0.043 x =228 of ∧ NH 4 OH ∞

Q. The conductivities at infinite dilution of $N H_{4} Cl, N a O H$ and $N a Cl$ are $130, 218, 120 o h m^{- 1} c m^{2} e q^{- 1} .$ If equivalent conductance of $\frac{N}{100}$ solution of $N H_{4} O H$ is 10 , then degree of dissociation of $N H_{4} O H$ at this dilution is

0.005

0.043

0.01

0.02

$130 + 218 = 120 + x$
$α = \frac{\land _{m}^{C}}{\land _{m}^{\infty}} = \frac{10}{228} = 0.043$
$x = 228$ of $\land_{N H_{4} O H}^{\infty}$

Q. The conductivities at infinite dilution of NH4​Cl,NaOH and NaCl are 130,218,120ohm−1cm2eq−1. If equivalent conductance of 100N​ solution of NH4​OH is 10 , then degree of dissociation of NH4​OH at this dilution is