Given equation of the line is lx+my+n=0 ⇒my=−lx−n ⇒y=m−lx−mn
On comparing with y=Mx+C, we get M=m−l and C=m−n
Again, given equation of the parabola is y2=8x
On comparing with y2=4ax, we get 4a=8⇒a=2
Now, by condition of tangency, C=Ma ⇒m−n=−1/m2 [from Eq.(i)] ⇒mn=l2m⇒ln=2m2