The condition for obtaining secondary maxima in the diffraction pattern due to single slit is

Question

The condition for obtaining secondary maxima in the diffraction pattern due to single slit is (A)  a sin θ =(nλ /2)  (B)  a sin θ =(2n-1)λ /2  (C)  a sin θ =nλ  (D)  a sin θ =(2n-1)λ

Tardigrade Admin · Accepted Answer

a sin θ =(2n-1)λ /2 is the condition for obtaining secondary maxima in the diffraction pattern due to single slit.

Q. The condition for obtaining secondary maxima in the diffraction pattern due to single slit is

$a sin θ = \frac{nλ}{2}$

$a sin θ = (2 n - 1) λ /2$

$a sin θ = nλ$

$a sin θ = (2 n - 1) λ$

a $sin θ = (2 n - 1) λ /2$
is the condition for obtaining secondary maxima in the diffraction pattern due to single slit.

Q. The condition for obtaining secondary maxima in the diffraction pattern due to single slit is

asinθ=2nλ​

asinθ=(2n−1)λ/2

asinθ=nλ

asinθ=(2n−1)λ

a sinθ=(2n−1)λ/2 is the condition for obtaining secondary maxima in the diffraction pattern due to single slit.

$a sin θ = \frac{nλ}{2}$

$a sin θ = (2 n - 1) λ /2$

$a sin θ = nλ$

$a sin θ = (2 n - 1) λ$

a $sin θ = (2 n - 1) λ /2$
is the condition for obtaining secondary maxima in the diffraction pattern due to single slit.