The concentration of R in the reaction R arrow P was measured as a function of time and the following data is obtained: [R] (molar) 1.0 0.75 0.40 0.10 t(min.) 0.0 0.05 0.12 0.18 The order of the reaction is

Question

The concentration of R in the reaction R arrow P was measured as a function of time and the following data is obtained: [R] (molar) 1.0 0.75 0.40 0.10 t(min.) 0.0 0.05 0.12 0.18 The order of the reaction is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

From two data, (for zero order kinetics) K I=( x / t )=(0.25/0.05)=5 K II =( x / t )=(0.60/0.12)=5

Q. The concentration of $R$ in the reaction $R \to P$ was measured as a function of time and the following data is obtained:

[R] (molar) 1.0 0.75 0.40 0.10

t(min.) 0.0 0.05 0.12 0.18

The order of the reaction is______

From two data, (for zero order kinetics)
$K_{I} = \frac{x}{t} = \frac{0.25}{0.05} = 5$
$K_{II} = \frac{x}{t} = \frac{0.60}{0.12} = 5$

Q. The concentration of R in the reaction R→P was measured as a function of time and the following data is obtained: [R] (molar) 1.0 0.75 0.40 0.10 t(min.) 0.0 0.05 0.12 0.18 The order of the reaction is______

From two data, (for zero order kinetics) KI​=tx​=0.050.25​=5 KII​=tx​=0.120.60​=5

Q. The concentration of $R$ in the reaction $R \to P$ was measured as a function of time and the following data is obtained:

[R] (molar) 1.0 0.75 0.40 0.10

t(min.) 0.0 0.05 0.12 0.18

The order of the reaction is______

From two data, (for zero order kinetics)
$K_{I} = \frac{x}{t} = \frac{0.25}{0.05} = 5$
$K_{II} = \frac{x}{t} = \frac{0.60}{0.12} = 5$