The concentration of a reactant X decreases from 0.1 M to 0.005 M in 40 min. If the reaction follows first order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

Question

The concentration of a reactant X decreases from 0.1 M to 0.005 M in 40 min. If the reaction follows first order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be (A)  1.73× 10-4 M min -1  (B)  3.47× 10-4 M min -1  (C)  3.47× 10-5 M min -1  (D)  7.5× 10-4 M min -1

Tardigrade Admin · Accepted Answer

k=(2.303/t) log (A0/A) =(2.303/40) log (0.1/0.005) =(2.303/40) log 20 =0.075 Rate of reaction when concentration of X is 0.01 M will be 0.075× 0.01=7.5× 10-4M text min -1

Q. The concentration of a reactant X decreases from 0.1 M to 0.005 M in 40 min. If the reaction follows first order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

$1.73 \times 10^{- 4} M min^{- 1}$

$3.47 \times 10^{- 4} M min^{- 1}$

$3.47 \times 10^{- 5} M min^{- 1}$

$7.5 \times 10^{- 4} M min^{- 1}$

$k = \frac{2.303}{t} lo g \frac{A _{0}}{A}$ $= \frac{2.303}{40} lo g \frac{0.1}{0.005}$ $= \frac{2.303}{40} lo g 20$ $= 0.075$ Rate of reaction when concentration of X is 0.01 M will be $0.075 \times 0.01 = 7.5 \times 10^{- 4} M min^{- 1}$

Q. The concentration of a reactant X decreases from 0.1 M to 0.005 M in 40 min. If the reaction follows first order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

1.73×10−4Mmin−1

3.47×10−4Mmin−1

3.47×10−5Mmin−1

7.5×10−4Mmin−1

k=t2.303​logAA0​​ =402.303​log0.0050.1​ =402.303​log20 =0.075 Rate of reaction when concentration of X is 0.01 M will be 0.075×0.01=7.5×10−4Mmin−1

$1.73 \times 10^{- 4} M min^{- 1}$

$3.47 \times 10^{- 4} M min^{- 1}$

$3.47 \times 10^{- 5} M min^{- 1}$

$7.5 \times 10^{- 4} M min^{- 1}$

$k = \frac{2.303}{t} lo g \frac{A _{0}}{A}$ $= \frac{2.303}{40} lo g \frac{0.1}{0.005}$ $= \frac{2.303}{40} lo g 20$ $= 0.075$ Rate of reaction when concentration of X is 0.01 M will be $0.075 \times 0.01 = 7.5 \times 10^{- 4} M min^{- 1}$