The compressibility of water is 4× 10- 5 per unit atmospheric pressure. The decrease in volume of 100 cm3 of water under a pressure of 100 atm will be

Question

The compressibility of water is 4× 10- 5 per unit atmospheric pressure. The decrease in volume of 100 cm3 of water under a pressure of 100 atm will be (A) 0.4 cm3 (B) 4× 10- 5 cm3 (C) 0.025 cm3 (D) 0.004 cm3

Tardigrade Admin · Accepted Answer

K=(1/B)=((Δ V/V)/P) . Here, P=100 atm , K=4× 10- 5 and V=100 cm3 Hence, Δ V=0.4 cm3

Q. The compressibility of water is $4 \times 1 0^{- 5}$ per unit atmospheric pressure. The decrease in volume of $100 c m^{3}$ of water under a pressure of $100 a t m$ will be

$0.4 c m^{3}$

$4 \times 1 0^{- 5} c m^{3}$

$0.025 c m^{3}$

$0.004 c m^{3}$

$K = \frac{1}{B} = \frac{\frac{Δ V}{V}}{P}$ .
Here, $P = 100 a t m$ ,
$K = 4 \times 1 0^{- 5}$ and
$V = 100 c m^{3}$
Hence, $Δ V = 0.4 c m^{3}$

Q. The compressibility of water is 4×10−5 per unit atmospheric pressure. The decrease in volume of 100cm3 of water under a pressure of 100atm will be

0.4cm3

4×10−5cm3

0.025cm3

0.004cm3