Question

The compressibility of water is $4\times 10^{- 5}$ per unit atmospheric pressure. The decrease in volume of $100 \, cm^{3}$ of water under a pressure of $100 \, atm$ will be

• A. $0.4 \, cm^{3}$
• B. $4\times 10^{- 5} \, cm^{3}$
• C. $0.025 \, cm^{3}$
• D. $0.004 \, cm^{3}$

Answer 1

Answer: (A)

$K=\frac{1}{B}=\frac{\frac{\Delta V}{V}}{P}$ .
Here, $P=100 \, atm$ ,
$K=4\times 10^{- 5}$ and
$V=100 \, cm^{3}$
Hence, $\Delta V=0.4 \, cm^{3}$