The compressibility of a gas is less than unity at STP. Therefore

Question

The compressibility of a gas is less than unity at STP. Therefore (A) Vm > 22.4 L (B) Vm < 22.4 L (C) Vm = 22.4 L (D) Vm = 44.8 L

Tardigrade Admin · Accepted Answer

Compressibility factor, z=(PV/nRT) Given, z < 1 ∴ (PV/nRT) < 1 or PV < nRT or , 1 atm × Vm < 1 mole ×0.0821 lit atm K-1mole-1×273 K or, Vm< (0.0821×273) lit or, Vm< 22.4 lit

Q. The compressibility of a gas is less than unity at STP. Therefore

$V_{m} > 22.4 L$

$V_{m} < 22.4 L$

$V_{m} = 22.4 L$

$V_{m} = 44.8 L$

Compressibility factor, $z = \frac{P V}{n RT}$
Given, $z < 1$
$∴ \frac{P V}{n RT} < 1$ or $P V < n RT$
or , $1 a t m \times V_{m} < 1$ mole $\times 0.0821$ lit atm
$K^{- 1} m o l e^{- 1} \times 273 K$
or, $V_{m} < (0.0821 \times 273)$ lit
or, $V_{m} < 22.4$ lit

Q. The compressibility of a gas is less than unity at STP. Therefore

Vm​>22.4L

Vm​<22.4L

Vm​=22.4L

Vm​=44.8L

Compressibility factor, z=nRTPV​ Given, z<1 ∴nRTPV​<1 or PV<nRT or , 1atm×Vm​<1 mole ×0.0821 lit atm K−1mole−1×273K or, Vm​<(0.0821×273) lit or, Vm​<22.4 lit

$V_{m} > 22.4 L$

$V_{m} < 22.4 L$

$V_{m} = 22.4 L$

$V_{m} = 44.8 L$

Compressibility factor, $z = \frac{P V}{n RT}$
Given, $z < 1$
$∴ \frac{P V}{n RT} < 1$ or $P V < n RT$
or , $1 a t m \times V_{m} < 1$ mole $\times 0.0821$ lit atm
$K^{- 1} m o l e^{- 1} \times 273 K$
or, $V_{m} < (0.0821 \times 273)$ lit
or, $V_{m} < 22.4$ lit