The compounds formed by the reaction of ammonia with chlorine and iodine are respectively

Question

The compounds formed by the reaction of ammonia with chlorine and iodine are respectively (A) NCl3 and NI3 (B) NCl3 and NH4I (C) NH4Cl and NH4I (D) NCl3 and (.NI3.NH3.)

Tardigrade Admin · Accepted Answer

Ammonia on reaction with chlorine and iodine gives NCl3 and (.NI3.NH3.) respectively as follows NH3+ undersete x c e s s3 C l2 arrow NCl3+3HCl 2NH3+3I2 arrow NI3.NH3+3HI

Q. The compounds formed by the reaction of ammonia with chlorine and iodine are respectively

$NC l_{3}$ and $N I_{3}$

$NC l_{3}$ and $N H_{4} I$

$N H_{4} Cl$ and $N H_{4} I$

$NC l_{3}$ and $(N I_{3} . N H_{3})$

Ammonia on reaction with chlorine and iodine gives $NC l_{3}$ and $(N I_{3} . N H_{3})$ respectively as follows

$N H_{3} + e x cess 3 C l_{2} \to NC l_{3} + 3 H Cl$

$2 N H_{3} + 3 I_{2} \to N I_{3} . N H_{3} + 3 H I$

Q. The compounds formed by the reaction of ammonia with chlorine and iodine are respectively

NCl3​ and NI3​

NCl3​ and NH4​I

NH4​Cl and NH4​I

NCl3​ and (NI3​.NH3​)

Ammonia on reaction with chlorine and iodine gives NCl3​ and (NI3​.NH3​) respectively as follows NH3​+excess3Cl2​​→NCl3​+3HCl 2NH3​+3I2​→NI3​.NH3​+3HI

$NC l_{3}$ and $N I_{3}$

$NC l_{3}$ and $N H_{4} I$

$N H_{4} Cl$ and $N H_{4} I$

$NC l_{3}$ and $(N I_{3} . N H_{3})$

Ammonia on reaction with chlorine and iodine gives $NC l_{3}$ and $(N I_{3} . N H_{3})$ respectively as follows

$N H_{3} + e x cess 3 C l_{2} \to NC l_{3} + 3 H Cl$

$2 N H_{3} + 3 I_{2} \to N I_{3} . N H_{3} + 3 H I$