The compound which forms a dative bond with ammonia, is:

Question

The compound which forms a dative bond with ammonia, is: (A)  CCl4  (B)  BCl3  (C)  MgCl2  (D)  NaCl

Tardigrade Admin · Accepted Answer

NH3 (ammonia) is a Lewis base (as it has a lone pair to donate), hence, it can form adduct with BaCl3 (a Lewis acid) by dative or co-ordinate bond. H-- undersetH oversetH mathop underset| overset| mathopN : xrightarrow undersetCl oversetCl mathop underset| overset| mathopB --Cl

Q. The compound which forms a dative bond with ammonia, is:

$CC l_{4}$

$BC l_{3}$

$M g C l_{2}$

$N a Cl$

$N H_{3}$ (ammonia) is a Lewis base (as it has a lone pair to donate), hence, it can form adduct with $B a C l_{3}$ (a Lewis acid) by dative or co-ordinate bond. $H - - H ∣ N ∣ H : Cl ∣ B ∣ Cl - - Cl$

Q. The compound which forms a dative bond with ammonia, is:

CCl4​

BCl3​

MgCl2​

NaCl

NH3​ (ammonia) is a Lewis base (as it has a lone pair to donate), hence, it can form adduct with BaCl3​ (a Lewis acid) by dative or co-ordinate bond. H−−H∣N∣​H​​:​Cl∣B∣​Cl​​−−Cl

$CC l_{4}$

$BC l_{3}$

$M g C l_{2}$

$N a Cl$

$N H_{3}$ (ammonia) is a Lewis base (as it has a lone pair to donate), hence, it can form adduct with $B a C l_{3}$ (a Lewis acid) by dative or co-ordinate bond. $H - - H ∣ N ∣ H : Cl ∣ B ∣ Cl - - Cl$