The compound which does not exhibit geometrical isomerism, is

Question

The compound which does not exhibit geometrical isomerism, is (A)  CH3CH = CHCOOH  (B)  Br — CH = CH — Br  (C)  C6H5CH = NOH  (D)

Tardigrade Admin · Accepted Answer

In case of acyclic compounds, presence of atleast one double bond between two carbon atoms or between carbon and nitrogen atoms is an essential condition for exhibiting geometrical isomerism. In case of cyclic compounds, different groups are present at the same carbon atoms and atleast one same group is present at successive carbon atoms.

does not satisfy these conditions, thus it does not exhibit geometrical isomerism.

Q. The compound which does not exhibit geometrical isomerism, is

$C H_{3} C H = C H COO H$

$B r — C H = C H — B r$

$C_{6} H_{5} C H = NO H$

Q. The compound which does not exhibit geometrical isomerism, is

CH3​CH=CHCOOH

Br—CH=CH—Br

C6​H5​CH=NOH

$C H_{3} C H = C H COO H$

$B r — C H = C H — B r$

$C_{6} H_{5} C H = NO H$