Question

The compound ${\left(Si{H}_3\right)}_{3}N$ is expected to be

• A. pyramidal and more basic than ${\left(C{H}_3\right)}_{3}N$
• B. planar and less basic than ${\left(C{H}_3\right)}_{3}N$
• C. pyramidal and less basic than ${\left(C{H}_3\right)}_{3}N$
• D. planar and more basic than ${\left(C{H}_3\right)}_{3}N$

Answer 1

Answer: (B)

${\left(Si{H}_3\right)}_{3}N$ is planar and less basic than ${\left(C{H}_3\right)}_{3}N$ because lone pair of N atom is used in $p\pi -d\pi$ back bonding with Si atom.