The compound H2N-Hg-O-Hg-I is formed by the action of

Question

The compound H2N-Hg-O-Hg-I is formed by the action of (A) NH3 and HgO in the presence of iodine (B) NI3,HgO and H2O (C) NH3+K2HgI4 (D) KI+NH3+Hg

Tardigrade Admin · Accepted Answer

The compound H2N-Hg-O-Hg-I is formed by the reaction of NH3 and K2HgI4 (Nesslar's reagent). NH 3+2 K 2 HgI 4+3 KOH arrow H 2 N - Hg - O - Hg - I +7 KI +2 H 2 O (Iodide of millon's base)

Q. The compound $H_{2} N - H g - O - H g - I$ is formed by the action of

$N H_{3}$ and HgO in the presence of iodine

$N I_{3}, H g O$ and $H_{2} O$

$N H_{3} + K_{2} H g I_{4}$

$K I + N H_{3} + H g$

The compound $H_{2} N - H g - O - H g - I$ is formed by the reaction of $N H_{3}$ and $K_{2} H g I_{4}$ (Nesslar's reagent).

$N H_{3} + 2 K_{2} H g I_{4} + 3 K O H$ $\to H_{2} N - H g - O - H g - I + 7 K I + 2 H_{2} O$ (Iodide of millon's base)

Q. The compound H2​N−Hg−O−Hg−I is formed by the action of

NH3​ and HgO in the presence of iodine

NI3​,HgO and H2​O

NH3​+K2​HgI4​

KI+NH3​+Hg