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Chemistry
The compound H2N-Hg-O-Hg-I is formed by the action of
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Q. The compound $H_{2}N-Hg-O-Hg-I$ is formed by the action of
NTA Abhyas
NTA Abhyas 2020
The p-Block Elements - Part2
A
$NH_{3}$ and HgO in the presence of iodine
27%
B
$NI_{3},HgO$ and $H_{2}O$
7%
C
$NH_{3}+K_{2}HgI_{4}$
61%
D
$KI+NH_{3}+Hg$
4%
Solution:
The compound $H_{2}N-Hg-O-Hg-I$ is formed by the reaction of $NH_{3}$ and $K_{2}HgI_{4}$ (Nesslar's reagent).
$NH _{3}+2 K _{2} HgI _{4}+3 KOH$ $\rightarrow H _{2} N - Hg - O - Hg - I +7 KI +2 H _{2} O$ (Iodide of millon's base)