The composition of wustite is Fe0.95O1 . What is the percentage of iron as Fe3 + ions?

Question

The composition of wustite is Fe0.95O1 . What is the percentage of iron as Fe3 + ions? (A) 10.5 (B) 25 (C) 35 (D) 45

Tardigrade Admin · Accepted Answer

Fe0.95O1 Let there are x ions of Fe3 + then (0.95 - x) ions will be Fe2 + . Compound is electrically neutral. +3x+2(.0.95-x.)-2=0 3x+1.90-2x-2=0 x=0.1 %Fe3 +=(0.1/0.95)× 100 =10.5

Q. The composition of wustite is $F e_{0.95} O_{1}$ . What is the percentage of iron as $F e^{3 +}$ ions?

10.5

25

35

45

$F e_{0.95} O_{1}$
Let there are x ions of $F e^{3 +}$ then $(0.95 - x)$ ions will be $F e^{2 +}$ . Compound is electrically neutral.
$+ 3 x + 2 (0.95 - x) - 2 = 0$
$3 x + 1.90 - 2 x - 2 = 0$
$x = 0.1$
$% F e^{3 +} = \frac{0.1}{0.95} \times 100$
$= 10.5$

Q. The composition of wustite is Fe0.95​O1​ . What is the percentage of iron as Fe3+ ions?

10.5

25

35

45

Fe0.95​O1​ Let there are x ions of Fe3+ then (0.95−x) ions will be Fe2+ . Compound is electrically neutral. +3x+2(0.95−x)−2=0 3x+1.90−2x−2=0 x=0.1 %Fe3+=0.950.1​×100 =10.5

Q. The composition of wustite is $F e_{0.95} O_{1}$ . What is the percentage of iron as $F e^{3 +}$ ions?

$F e_{0.95} O_{1}$
Let there are x ions of $F e^{3 +}$ then $(0.95 - x)$ ions will be $F e^{2 +}$ . Compound is electrically neutral.
$+ 3 x + 2 (0.95 - x) - 2 = 0$
$3 x + 1.90 - 2 x - 2 = 0$
$x = 0.1$
$% F e^{3 +} = \frac{0.1}{0.95} \times 100$
$= 10.5$