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Q.
The composition of wustite is $Fe_{0.95}O_{1}$ . What is the percentage of iron as $Fe^{3 +}$ ions?
NTA AbhyasNTA Abhyas 2022
Solution:
$Fe_{0.95}O_{1}$
Let there are x ions of $Fe^{3 +}$ then $\left(0.95 - x\right)$ ions will be $Fe^{2 +}$ . Compound is electrically neutral.
$+3x+2\left(\right.0.95-x\left.\right)-2=0$
$3x+1.90-2x-2=0$
$x=0.1$
$\%Fe^{3 +}=\frac{0.1}{0.95}\times 100$
$=10.5$