The complex showing a spin only magnetic moment of 2.82 BM is

Question

The complex showing a spin only magnetic moment of 2.82 BM is (A) Ni(CO)4  (B) [NiCl4]2-  (C) Ni(PPh3)4  (D) [Ni(CN)4]2-

Tardigrade Admin · Accepted Answer

Magnetic moment =2.83 BM indicates that there is two unpaired electrons. μ = √ n(n+2) BM= √ 8 BM=2.82 BM In [NiCI4]2-,Ni has d8 configuration and Cl- is a weak ligand:

Q. The complex showing a spin only magnetic moment of $2.82 BM$ is

$N i (CO)_{4}$

$[N i C l_{4}]^{2 -}$

$N i (PP h_{3})_{4}$

$[N i (CN)_{4}]^{2 -}$

Magnetic moment $= 2.83 BM$
indicates that there is two unpaired electrons.
$μ = n (n + 2) BM = 8 BM = 2.82 BM$
In $[N i C I_{4}]^{2 -}, N i$ has $d^{8}$ configuration
and $C l^{-}$ is a weak ligand:

Q. The complex showing a spin only magnetic moment of 2.82BM is

Ni(CO)4​

[NiCl4​]2−

Ni(PPh3​)4​

[Ni(CN)4​]2−