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Question
Mathematics
The complex number z=x+i y which satisfy the equation |(z-5 i/z+5 i)|=1, lie on
Q. The complex number
z
=
x
+
i
y
which satisfy the equation
∣
∣
z
+
5
i
z
−
5
i
∣
∣
=
1
, lie on
1674
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Manipal
Manipal 2012
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A
the x-axis
B
the straight line y=5
C
a circle passing through the origin
D
None of the above
Solution:
∣
z
+
5
i
z
−
5
i
∣
=
1
⇒
∣
z
−
5
i
∣
=
∣
z
+
5
i
∣
(Using definition
∣
z
−
z
1
∣
=
∣
z
−
z
2
∣
gives Perpendicular bisector of
z
1
and
z
2
)
⇒
Perpendicular bisector of points
(
0
,
5
)
and
(
0
,
−
5
)
which lies on
y
-axis.