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Tardigrade
Question
Mathematics
The common tangent to the circles x2 + y2 = 4 and x2 + y2 + 6x + 8y - 24 = 0 also passes through the point :
Q. The common tangent to the circles
x
2
+
y
2
=
4
and
x
2
+
y
2
+
6
x
+
8
y
−
24
=
0
also passes through the point :
1338
298
JEE Main
JEE Main 2019
Conic Sections
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A
(-4, 6)
4%
B
(6, -2)
72%
C
(-6, 4)
8%
D
(4, -2)
16%
Solution:
Circle touches internally
C
1
(
0
,
0
)
;
r
1
=
2
C
2
:
(
−
3
,
−
4
)
;
r
2
=
7
C
1
C
2
=
∣
r
1
−
r
2
∣
S
1
−
S
2
=
0
⇒
eqn. of common tangent
6
x
+
8
y
−
20
=
0
3
x
+
4
y
=
10
(
6
,
−
2
)
satisfy it