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Tardigrade
Question
Physics
The combination of gates shown below yields
Q. The combination of gates shown below yields
2289
171
BITSAT
BITSAT 2014
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A
OR gate
50%
B
NOT gate
40%
C
XOR gate
0%
D
NAND gate
10%
Solution:
The final bolean expression is,
X
=
(
A
.
B
)
=
A
+
B
=
A
+
B
⇒
OR
gate
