Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The coefficient of x in f(x)=| beginmatrix x 1+ sin x cos x 1 log (1+x) 2 x2 1+x2 0 endmatrix |,-1 < x le 1, is
Q. The coefficient of
x
in
f
(
x
)
=
∣
∣
x
1
x
2
1
+
sin
x
lo
g
(
1
+
x
)
1
+
x
2
cos
x
2
0
∣
∣
,
−
1
<
x
≤
1
,
is
2572
189
KEAM
KEAM 2007
Determinants
Report Error
A
1
12%
B
−
2
53%
C
−
1
18%
D
0
12%
E
2
12%
Solution:
f
(
x
)
=
∣
∣
x
1
x
2
1
+
sin
x
lo
g
(
1
+
x
)
1
+
x
2
cos
x
2
0
∣
∣
=
x
{
−
2
(
1
+
x
2
)}
−
(
1
+
sin
x
)
(
−
2
x
2
)
+
cos
x
{
1
+
x
2
−
x
2
lo
g
(
1
+
x
)}
=
−
2
x
−
2
x
3
+
2
x
2
+
2
x
2
sin
x
+
cos
x
{
1
+
x
2
−
x
2
lo
g
(
1
+
x
)}
∴
Coefficient of
x
in
f
(
x
)
=
−
2