Let V0 be the initial volume of glycerine, i.e, at 0∘C (dry). If Vt be its volume at 30∘C
Then Vt=V0(1+γΔt) =V0(1+49×(10)−5×30) Vt=V0(1+0.01470)=1.01470V0 ⇒VtV0=1.014701
Let ρo and ρt be the initial and final densities of glycerine then initial density, ρ0=V0m and final density, ρt=Vtm
Where, m= mass of glycerine ρ0Δρ= fractional change in the density (ρ)0(ρ)t−(ρ)0=V0mm(Vt1−V01)=(VtV0−1) (ρ)0Δρ=(1.014701−1)=−0.0145
Here, negative sign shows that density decreases with rise in temperature ∣∣ρ0Δρ∣∣=0.0145=1.45×10−2