The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is (Take g=10 m s-2)

Question

The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is (Take g=10 m s-2) (A) √15 m s-1 (B) √3 m s-1 (C) √30 m s-1 (D) √10 m s-1

Tardigrade Admin · Accepted Answer

Here, r=3 m, μ=0.1, g =10 m s-2 The maximum speed with which a cyclist can take a turn without skidding is =√μ rg =√0.1×(3 m)(10m s-2) =√3 m s-1

Q. The coefficient of friction between the tyres and the road is $0.1$ . The maximum speed with which a cyclist can take a circular turn of radius $3 m$ without skidding is
(Take $g = 10 m s^{- 2}$ )

$15 m$ $s^{- 1}$

$3 m$ $s^{- 1}$

$30 m$ $s^{- 1}$

$10 m$ $s^{- 1}$

Here, $r = 3 m$ , $μ = 0.1, g$ $= 10 m s^{- 2}$
The maximum speed with which a cyclist can take a turn without skidding is
$= μ r g$ $= 0.1 \times (3 m) (10 m s^{- 2})$ $= 3 m$ $s^{- 1}$

Q. The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3m without skidding is (Takeg=10ms−2)

15​m s−1

3​m s−1

30​m s−1

10​m s−1