The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance X to it before addition of 1 mL of 10 % NaCl solution. The gold number of X is

Question

The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance X to it before addition of 1 mL of 10 % NaCl solution. The gold number of X is (A) 0.25 (B) 25 (C) 250 (D) 2.5

Tardigrade Admin · Accepted Answer

Number of milligrams of protective colloid added in

10 m L

of colloidal gold to prevent its coagulation on addition of

1 m L

of

10% N a Cl

solution is called its gold number.

∴

Gold number of present colloid

= 25

Q. The coagulation of 100mL of colloidal solution of gold is completely prevented by addition of 0.25g of a substance X to it before addition of 1mL of 10%NaCl solution. The gold number of X is

0.25

25

250

2.5

Number of milligrams of protective colloid added in 10mL of colloidal gold to prevent its coagulation on addition of 1mL of 10%NaCl solution is called its gold number. ∴ Gold number of present colloid =25

Q. The coagulation of $100 m L$ of colloidal solution of gold is completely prevented by addition of $0.25 g$ of a substance $X$ to it before addition of $1 m L$ of $10% N a Cl$ solution. The gold number of $X$ is

Number of milligrams of protective colloid added in $10 m L$ of colloidal gold to prevent its coagulation on addition of $1 m L$ of $10% N a Cl$ solution is called its gold number.
$∴$ Gold number of present colloid $= 25$