The co-ordination number and oxidation number of X in the following compound [X(SO4)(NH3)5]Cl will be:

Question

The co-ordination number and oxidation number of X in the following compound [X(SO4)(NH3)5]Cl will be: (A) 10 and 3 (B) 2 and 6 (C) 6 and 3 (D) 6 and 4

Tardigrade Admin · Accepted Answer

Co-ordination number is the number of ligands a-bonded to metal-atom. Hence, co-ordination number of

X

in

[X (S O_{4}) (N H_{3})_{5}] Cl

is

6

.
Let oxidation state of

X

in the complex be

y

, then-

y + (- 2) + 5 (0) + (- 1) = 0

y - 2 - 1 = 0

y = + 3

Q. The co-ordination number and oxidation number of X in the following compound [X(SO4​)(NH3​)5​]Cl will be:

10 and 3

2 and 6

6 and 3

6 and 4

Co-ordination number is the number of ligands a-bonded to metal-atom. Hence, co-ordination number of X in [X(SO4​)(NH3​)5​]Cl is 6. Let oxidation state of X in the complex be y, then- y+(−2)+5(0)+(−1)=0 y−2−1=0 y=+3

Q. The co-ordination number and oxidation number of $X$ in the following compound $[X (S O_{4}) (N H_{3})_{5}] Cl$ will be:

Co-ordination number is the number of ligands a-bonded to metal-atom. Hence, co-ordination number of $X$ in $[X (S O_{4}) (N H_{3})_{5}] Cl$ is $6$ .
Let oxidation state of $X$ in the complex be $y$ , then-
$y + (- 2) + 5 (0) + (- 1) = 0$
$y - 2 - 1 = 0$
$y = + 3$