The given equation xy+2x+2y+4=0 can be rewritten as (x+2)(y+2)=0 or x+2=0y+2=0
And also given that x+y+2=0
On solving the above equations, we get A(−2,0),B(0,−2),C(−2,−2)
It is clearly that ΔABC is right angled triangle with right angle at C.
Hence, centre of the circumcircle is the mid point of AB whose coordinates are (−1,−1)