The circuit shown in the diagram contains two diodes, each with a forward resistance of 30 Ω and infinite reverse resistance. If the battery is of 3 V, then the voltage drop across 50 Ω resistance will be

Question

The circuit shown in the diagram contains two diodes, each with a forward resistance of 30 Ω and infinite reverse resistance. If the battery is of 3 V, then the voltage drop across 50 Ω resistance will be (A) 2 V (B) 5 V (C) 1 V (D) 1.5 V

Tardigrade Admin · Accepted Answer

Diode Di get reverse biased where as diode D2 get forward biased. Voltage drop across 50 Ω. resistance =((3/150)) × 50=1 V

Q. The circuit shown in the diagram contains two diodes, each with a forward resistance of $30 Ω$ and infinite reverse resistance. If the battery is of $3 V$ , then the voltage drop across $50 Ω$ resistance will be

2 V

5 V

1 V

1.5 V

Diode Di get reverse biased where as diode $D_{2}$ get forward biased.
Voltage drop across $50 Ω$ .
resistance $= (\frac{3}{150}) \times 50 = 1 V$

Q. The circuit shown in the diagram contains two diodes, each with a forward resistance of 30Ω and infinite reverse resistance. If the battery is of 3V, then the voltage drop across 50Ω resistance will be

2 V

5 V

1 V

1.5 V

Diode Di get reverse biased where as diode D2​ get forward biased. Voltage drop across 50Ω. resistance =(1503​)×50=1V

Q. The circuit shown in the diagram contains two diodes, each with a forward resistance of $30 Ω$ and infinite reverse resistance. If the battery is of $3 V$ , then the voltage drop across $50 Ω$ resistance will be

Diode Di get reverse biased where as diode $D_{2}$ get forward biased.
Voltage drop across $50 Ω$ .
resistance $= (\frac{3}{150}) \times 50 = 1 V$