The circuit shown below contains two ideal diodes, each with a forward resistance of 50 Ω . If the battery voltage is 6 V, the current through the 100 Ω resistance (in Amperes) is :

Question

The circuit shown below contains two ideal diodes, each with a forward resistance of 50 Ω . If the battery voltage is 6 V, the current through the 100 Ω resistance (in Amperes) is : (A) 0.027 (B) 0.020 (C) 0.030 (D) 0.036

Tardigrade Admin · Accepted Answer

I = (6/300) = 0.002 (D2 is in reverse bias)

Q. The circuit shown below contains two ideal diodes, each with a forward resistance of $50 Ω$ . If the battery voltage is $6 V$ , the current through the $100 Ω$ resistance (in Amperes) is :

0.027

0.020

0.030

0.036

$I = \frac{6}{300} = 0.002$ ( $D_{2}$ is in reverse bias)

Q. The circuit shown below contains two ideal diodes, each with a forward resistance of 50Ω . If the battery voltage is 6V, the current through the 100Ω resistance (in Amperes) is :