The circuit has two oppositely connect ideal diodes in parallel. What is the current flowing in the circuit?

Question

The circuit has two oppositely connect ideal diodes in parallel. What is the current flowing in the circuit? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-kjnc9ikzzaz88hob.jpg" /> (A) 1.33 A (B) 1.71 A (C) 2.00 A (D) 2.71 A

Tardigrade Admin · Accepted Answer

Since diode textitD1 is reverse biased, therefore it will act as an open circuit. The effective resistance of the circuit is textitR=4+2=6 Ω . Current in the circuit is textitI = textitE / textitR = text12 / 6 = 2 A.

Q. The circuit has two oppositely connect ideal diodes in parallel. What is the current flowing in the circuit?

$1.33 A$

$1.71 A$

$2.00 A$

$2.71 A$

Since diode $D_{1}$ is reverse biased, therefore it will act as an open circuit.
The effective resistance of the circuit is $R = 4 + 2 = 6 Ω$ .
Current in the circuit is $I = E / R = 12 /6 = 2 A$ .

Q. The circuit has two oppositely connect ideal diodes in parallel. What is the current flowing in the circuit?

1.33A

1.71A

2.00A

2.71A

Since diode D1​ is reverse biased, therefore it will act as an open circuit. The effective resistance of the circuit is R=4+2=6Ω . Current in the circuit is I=E/R=12/6=2A.

$1.33 A$

$1.71 A$

$2.00 A$

$2.71 A$

Since diode $D_{1}$ is reverse biased, therefore it will act as an open circuit.
The effective resistance of the circuit is $R = 4 + 2 = 6 Ω$ .
Current in the circuit is $I = E / R = 12 /6 = 2 A$ .