Question

The circuit has two oppositely connect ideal diodes in parallel. What is the current flowing in the circuit?

• A. $1.33\,A$
• B. $1.71\,A$
• C. $2.00\,A$
• D. $2.71\,A$

Answer 1

Answer: (C)

Since diode $\textit{D}_{1}$ is reverse biased, therefore it will act as an open circuit.
The effective resistance of the circuit is $\textit{R}=4+2=6\,\Omega$ .
Current in the circuit is $\textit{I} = \textit{E} / \textit{R} = \text{12} / 6 = 2 \,A$.