The circuit contains two diodes each with a forward resistance of 50 Ω and with infinite reverse resistance. If the battery voltage is 6 V, the current through the 120 Ω resistance is mA.

Question

The circuit contains two diodes each with a forward resistance of 50 Ω and with infinite reverse resistance. If the battery voltage is 6 V, the current through the 120 Ω resistance is mA. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-r1xpwe8ge2fszxd2.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

D2 is reverse bias so current does not flow through D2. D1 is forward bias. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-r1xpwe8ge2fsj4z9.jpg" /> I=(6/300)⇒ 0.02 A =20 mA

Q. The circuit contains two diodes each with a forward resistance of $50 Ω$ and with infinite reverse resistance. If the battery voltage is $6 V,$ the current through the $120 Ω$ resistance is $m A .$

$D_{2}$ is reverse bias so current does not flow through $D_{2} .$
$D_{1}$ is forward bias.

$I = \frac{6}{300} \Rightarrow 0.02 A$
$= 20 m A$

Q. The circuit contains two diodes each with a forward resistance of 50Ω and with infinite reverse resistance. If the battery voltage is 6V, the current through the 120Ω resistance is mA.

D2​ is reverse bias so current does not flow through D2​. D1​ is forward bias. I=3006​⇒0.02A =20mA

Q. The circuit contains two diodes each with a forward resistance of $50 Ω$ and with infinite reverse resistance. If the battery voltage is $6 V,$ the current through the $120 Ω$ resistance is $m A .$

$D_{2}$ is reverse bias so current does not flow through $D_{2} .$
$D_{1}$ is forward bias.

$I = \frac{6}{300} \Rightarrow 0.02 A$
$= 20 m A$