The chord of the circle x2 +y2 -4x = 0 which is bisected at (1, 0) is perpendicular to the line .................

Question

The chord of the circle x2 +y2 -4x = 0 which is bisected at (1, 0) is perpendicular to the line ................. (A) x=1 (B) y=1 (C) y=x (D) x+y=0

Tardigrade Admin · Accepted Answer

Given, equation of circle x2+y2-4 x=0, bisect by (1,0) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/701c198359c53c0e41179a9af334cdbd-.png" /> Centre of circle =(2,0) Radius of circle =2 From figure, A B is the chord of circle which bisected by the point (1,0) and perpendicular to the line y=1. Because it is parallel to x -axis while chord is parallel to y -axis.

Q. The chord of the circle $x^{2} + y^{2} - 4 x = 0$ which is bisected at $(1, 0)$ is perpendicular to the line .................

$x = 1$

$y = 1$

$y = x$

$x + y = 0$

Q. The chord of the circle x2+y2−4x=0 which is bisected at (1,0) is perpendicular to the line .................

x=1

y=1

y=x

x+y=0

Given, equation of circle x2+y2−4x=0, bisect by (1,0) Centre of circle =(2,0) Radius of circle =2 From figure, AB is the chord of circle which bisected by the point (1,0) and perpendicular to the line y=1. Because it is parallel to x -axis while chord is parallel to y -axis.

Q. The chord of the circle $x^{2} + y^{2} - 4 x = 0$ which is bisected at $(1, 0)$ is perpendicular to the line .................

$x = 1$

$y = 1$

$y = x$

$x + y = 0$