Question

The chord of the circle $x^2 +y^2 -4x = 0$ which is bisected at $ (1, 0)$ is perpendicular to the line .................

• A. $x=1$
• B. $y=1$
• C. $y=x$
• D. $x+y=0$

Answer 1

Answer: (B)

Given, equation of circle
$x^{2}+y^{2}-4 x=0,$ bisect by (1,0)

Centre of circle $=(2,0)$
Radius of circle $=2$
From figure, $A B$ is the chord of circle which bisected by the point $(1,0)$ and perpendicular to the line $y=1$.
Because it is parallel to $x$ -axis while chord is parallel to $y$ -axis.