The chord of contact of the pair of tangents drawn from each point on the line 2 x+y=4 to the parabola y2=-4 x passes through a fixed point :

Question

The chord of contact of the pair of tangents drawn from each point on the line 2 x+y=4 to the parabola y2=-4 x passes through a fixed point : (A) (-2,1) (B) (-2,-1) (C) (1 / 2,1 / 4) (D) (-1 / 2,-1 / 4)

Tardigrade Admin · Accepted Answer

equation of the chord of contact is yy 1+2( x + x 1)=0 where 2 x1+y1=4 put y1=4-2 x1 in above and interpret the result

Q. The chord of contact of the pair of tangents drawn from each point on the line $2 x + y = 4$ to the parabola $y^{2} = - 4 x$ passes through a fixed point :

$(- 2, 1)$

$(- 2, - 1)$

$(1/2, 1/4)$

$(- 1/2, - 1/4)$

equation of the chord of contact is $y y_{1} + 2 (x + x_{1}) = 0$ where $2 x_{1} + y_{1} = 4$ put $y_{1} = 4 - 2 x_{1}$ in above and interpret the result

Q. The chord of contact of the pair of tangents drawn from each point on the line 2x+y=4 to the parabola y2=−4x passes through a fixed point :

(−2,1)

(−2,−1)

(1/2,1/4)

(−1/2,−1/4)