The charge on 1 gram ions of Al3+ is

Question

The charge on 1 gram ions of Al3+ is (A) (1/27) NAe coulomb (B) (1/3) × NAe coulomb (C) (1/9) × NAe coulomb (D) 3 × NAe coulomb

Tardigrade Admin · Accepted Answer

So for finding the charge of one gram ion of

A l^{3 +}

, We have to know that 1 gm atom

= 1

mole of atom
So, charge on one mole of electron

= N_{a} \times

charge on

1 e^{-}

Thus, Charge on one mole of

A l^{3 +}

ion

= 3 \times N_{A} \times e

Since,

27 g

of

A l^{3 +}

ion having charge of

3 \times N_{A} \times e

.
Therefore,

1 g

of

A l^{3 +}

ion having charge

= \frac{3 \times N _{A} \times e}{27} C

.

= \frac{N _{a} e ^{-}}{9} C

Q. The charge on $1$ gram ions of $A l^{3 +}$ is