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Q. The charge on $1$ gram ions of $Al^{3+}$ is

Some Basic Concepts of Chemistry

Solution:

So for finding the charge of one gram ion of $Al ^{3+}$, We have to know that 1 gm atom $=1$ mole of atom
So, charge on one mole of electron $= N _{ a } \times$ charge on $1 e ^{-}$
Thus, Charge on one mole of $Al ^{3+}$ ion $=3 \times N _{ A } \times e$
Since, $27 g$ of $Al ^{3+}$ ion having charge of $3 \times N _{ A } \times e$.
Therefore, $1 g$ of $Al ^{3+}$ ion having charge $=\frac{3 \times N _{ A } \times e }{27} C$. $=\frac{ N _{ a } e ^{-}}{9} C$