The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is: (mass of the moon = 7.36 × 1022 kg, radius of the moon’s orbit = 3.8 × 108 m).

Question

The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is: (mass of the moon = 7.36 × 1022 kg, radius of the moon’s orbit = 3.8 × 108 m). (A) 6.73 × 10-5 m/s2 (B) 6.73 × 10-3 m/s2 (C) 6.73 × 10-2 m/s2 (D) 6.73 × 10-4 m/s2

Tardigrade Admin · Accepted Answer

Acceleration of earth due to moon =( GM text moon / r text orbital 2) Thus the change in acceleration due to two opposite orientations of earth is, (2 GM text moon / r text orbital 2)=6.73 × 10-5 m / s 2

Q. The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is:
(mass of the moon $= 7.36 \times 1 0^{22} k g$ , radius of the moon’s orbit $= 3.8 \times 1 0^{8} m$ ).

$6.73 \times 1 0^{- 5} m / s^{2}$

$6.73 \times 1 0^{- 3} m / s^{2}$

$6.73 \times 1 0^{- 2} m / s^{2}$

$6.73 \times 1 0^{- 4} m / s^{2}$

Acceleration of earth due to moon $= \frac{G M _{moon}}{r _{orbital}^{2}}$
Thus the change in acceleration due to two opposite orientations of earth is, $\frac{2 G M _{moon}}{r _{orbital}^{2}} = 6.73 \times 1 0^{- 5} m / s^{2}$

Q. The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is: (mass of the moon =7.36×1022kg, radius of the moon’s orbit =3.8×108m).

6.73×10−5m/s2

6.73×10−3m/s2

6.73×10−2m/s2

6.73×10−4m/s2