Question

The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is:
(mass of the moon $= 7.36 \times 10^{22}\, kg$, radius of the moon’s orbit $= 3.8 \times 10^8\,m$).

• A. $6.73 \times 10^{-5}\, m/s^2$
• B. $6.73 \times 10^{-3}\, m/s^2$
• C. $6.73 \times 10^{-2}\, m/s^2$
• D. $6.73 \times 10^{-4}\, m/s^2$

Answer 1

Answer: (A)

Acceleration of earth due to moon $=\frac{ GM _{\text {moon }}}{ r _{\text {orbital }}^{2}}$
Thus the change in acceleration due to two opposite orientations of earth is, $\frac{2 GM _{\text {moon }}}{ r _{\text {orbital }}^{2}}=6.73 \times 10^{-5} m / s ^{2}$