The change in entropy for the fusion of 1 mole of ice is [ textmp textof textice text= text273 textK, , molar enthalpy of fusion for ice = 6.0 textkJ textmo textl-1 ]

Question

The change in entropy for the fusion of 1 mole of ice is [ textmp textof textice text= text273 textK, , molar enthalpy of fusion for ice = 6.0 textkJ textmo textl-1 ] (A)  11.73 JK-1 mol-1  (B)  18.84 JK-1 mol-1  (C)  21.97 JK-1 mol-1  (D)  24.47 JK-1 mol-1

Tardigrade Admin · Accepted Answer

Entropy change of fusion Δ Sf=(Δ Hf/T) Δ Hf=60× 103 J mol-1,T=273 K Δ Sf=(60× 103/273) =21.97 J K -1 mol-1

Q. The change in entropy for the fusion of 1 mole of ice is [ $mp of ice = 273 K,$ , molar enthalpy of fusion for ice $= 6.0 kJ mo l^{- 1}$ ]

$11.73 J K^{- 1} m o l^{- 1}$

$18.84 J K^{- 1} m o l^{- 1}$

$21.97 J K^{- 1} m o l^{- 1}$

$24.47 J K^{- 1} m o l^{- 1}$

Entropy change of fusion
$Δ S_{f} = \frac{Δ H _{f}}{T}$
$Δ H_{f} = 60 \times 10^{3} J m o l^{- 1}, T = 273 K$
$Δ S_{f} = \frac{60 \times 10 ^{3}}{273}$
$= 21.97 J K^{- 1} m o l^{- 1}$

Q. The change in entropy for the fusion of 1 mole of ice is [ mpofice=273K, , molar enthalpy of fusion for ice =6.0kJmol−1 ]

11.73JK−1mol−1

18.84JK−1mol−1

21.97JK−1mol−1

24.47JK−1mol−1