The centre of a wheel rolling on a plane surface moves with a speed v 0. A particle on the rim of the wheel at the same level as the centre will be moving at speed

Question

The centre of a wheel rolling on a plane surface moves with a speed v 0. A particle on the rim of the wheel at the same level as the centre will be moving at speed (A) zero (B) v 0 (C) 2v 0 (D) √2vo

Tardigrade Admin · Accepted Answer

The given solution can be shown as <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/21037da3369038de53d7e996c5593da2-.png" /> Here v0 = Rω At P, v = r ω = √(R2 + R2)ω = √2 R ω = √2 v0

Q. The centre of a wheel rolling on a plane surface moves with a speed $v_{0}$ . A particle on the rim of the wheel at the same level as the centre will be moving at speed

zero

$v_{0}$

$2 v_{0}$

$2 v_{o}$

The given solution can be shown as

Here $v_{0} = R ω$
At $P, v = r ω$
$= (R^{2} + R^{2}) ω$
$= 2 R ω = 2 v_{0}$

Q. The centre of a wheel rolling on a plane surface moves with a speed v0​. A particle on the rim of the wheel at the same level as the centre will be moving at speed

zero

v0​

2v0​

2vo​​

The given solution can be shown as Here v0​=Rω At P,v=rω =(R2+R2)ω​ =2​Rω=2​v0​

Q. The centre of a wheel rolling on a plane surface moves with a speed $v_{0}$ . A particle on the rim of the wheel at the same level as the centre will be moving at speed

$v_{0}$

$2 v_{0}$

$2 v_{o}$

The given solution can be shown as

Here $v_{0} = R ω$
At $P, v = r ω$
$= (R^{2} + R^{2}) ω$
$= 2 R ω = 2 v_{0}$