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  4. The centre of a wheel rolling on a plane surface moves with a speed v 0. A particle on the rim of the wheel at the same level as the centre will be moving at speed

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Q. The centre of a wheel rolling on a plane surface moves with a speed $v_{ 0}$. A particle on the rim of the wheel at the same level as the centre will be moving at speed

VITEEEVITEEE 2013

Solution:

The given solution can be shown as
image
Here $v_0 = R\omega$
At $P, v = r \omega$
$= \sqrt{(R^2 + R^2)\omega}$
$ = \sqrt{2} R \omega = \sqrt{2} v_0$