The cell potential for the given cell at 298 K Pt mid H 2( g , 1 bar )| H +( aq ) | Cu 2+( aq )| Cu ( s ) is 0.31 V. The pH of the acidic solution is found to be 3 , whereas the concentration of Cu 2+ is 10-x M. The value of x is (Given: E Cu 2+ / Cu Θ=0.34 V and (2.303 RT / F )=0.06 V )

Question

The cell potential for the given cell at 298 K Pt mid H 2( g , 1 bar )| H +( aq ) | Cu 2+( aq )| Cu ( s ) is 0.31 V. The pH of the acidic solution is found to be 3 , whereas the concentration of Cu 2+ is 10-x M. The value of x is (Given: E Cu 2+ / Cu Θ=0.34 V and (2.303 RT / F )=0.06 V ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

H 2( g )+ Cu 2+( aq. ) arrow 2 H +(aq. )+ Cu ( s ) 0.31=0.34-(0.06/2) log ([ H +]2/[ Cu 2+]) [ Cu 2+]=10-7 M x =7

Q. The cell potential for the given cell at 298K Pt∣H2​(g,1 bar )∣∣​H+(aq)∥Cu2+(aq)∣∣​Cu(s) is 0.31V. The pH of the acidic solution is found to be 3 , whereas the concentration of Cu2+ is 10−xM. The value of x is___ (Given: ECu2+/CuΘ​=0.34V and F2.303RT​=0.06V )

H2​(g)+Cu2+( aq. )→2H+(aq. )+Cu(s) 0.31=0.34−20.06​log[Cu2+][H+]2​ [Cu2+]=10−7M x=7

$H_{2} (g) + C u^{2 +} ($ aq. $) \to 2 H^{+} ($ aq. $) + C u (s)$
$0.31 = 0.34 - \frac{0.06}{2} lo g \frac{[ H ^{+} ] ^{2}}{[ C u ^{2 +} ]}$
$[C u^{2 +}] = 1 0^{- 7} M$
$x = 7$