The carboxylic acid which reduces Tollens reagent is:

Question

The carboxylic acid which reduces Tollens reagent is: (A)  HCOOH  (B)  CH3COOH  (C)  CH3CH2COOH  (D)  CH3CH2CH2COOH

Tardigrade Admin · Accepted Answer

Formic acid reduces Tollen's reagent underset text Tollen's reagent 2 Ag ( NH 3)2++ underset text Formic acid HCOOH longrightarrow underset text Silver 2 Ag + CO 2 +2 NH 4++2 NH 3 Because it behave both on an acid and as an aldehyde <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/df42f3dccd79cca92067c8a0659bdb39-.png" />

Q. The carboxylic acid which reduces Tollens reagent is:

$H COO H$

$C H_{3} COO H$

$C H_{3} C H_{2} COO H$

$C H_{3} C H_{2} C H_{2} COO H$

Formic acid reduces Tollen's reagent
$Tollen’s reagent 2 A g (N H_{3})_{2}^{+} + Formic acid H COO H ⟶ Silver 2 A g + C O_{2}$
$+ 2 N H_{4}^{+} + 2 N H_{3}$
Because it behave both on an acid and as an aldehyde

Q. The carboxylic acid which reduces Tollens reagent is:

HCOOH

CH3​COOH

CH3​CH2​COOH

CH3​CH2​CH2​COOH

Formic acid reduces Tollen's reagent Tollen’s reagent 2Ag(NH3​)2+​​+ Formic acid HCOOH​⟶ Silver 2Ag​+CO2​ +2NH4+​+2NH3​ Because it behave both on an acid and as an aldehyde

$H COO H$

$C H_{3} COO H$

$C H_{3} C H_{2} COO H$

$C H_{3} C H_{2} C H_{2} COO H$

Formic acid reduces Tollen's reagent
$Tollen’s reagent 2 A g (N H_{3})_{2}^{+} + Formic acid H COO H ⟶ Silver 2 A g + C O_{2}$
$+ 2 N H_{4}^{+} + 2 N H_{3}$
Because it behave both on an acid and as an aldehyde