The capacity of a parallel plate condenser is 10 μ F, when the distance between its plates is 8 cm. If the distance between the plates is reduced to 4 cm, then the capacity of this parallel plate condenser will be

Question

The capacity of a parallel plate condenser is 10 μ F, when the distance between its plates is 8 cm. If the distance between the plates is reduced to 4 cm, then the capacity of this parallel plate condenser will be (A) 5 μ F (B) 10 μ F (C) 20 μ F (D) 40 μ F

Tardigrade Admin · Accepted Answer

C propto (1/d) ⇒ (C1/C2)=(d2/d1), so (C2/10)=(8/4) ⇒ C2=20 μ F

Q. The capacity of a parallel plate condenser is $10 μ F$ , when the distance between its plates is $8 c m$ . If the distance between the plates is reduced to $4 c m$ , then the capacity of this parallel plate condenser will be

$5 μ F$

$10 μ F$

$20 μ F$

$40 μ F$

$C \propto \frac{1}{d} \Rightarrow \frac{C _{1}}{C _{2}} = \frac{d _{2}}{d _{1}}$ ,
so $\frac{C _{2}}{10} = \frac{8}{4} \Rightarrow C_{2} = 20 μ F$

Q. The capacity of a parallel plate condenser is 10μF, when the distance between its plates is 8cm. If the distance between the plates is reduced to 4cm, then the capacity of this parallel plate condenser will be

5μF

10μF

20μF

40μF