The capacitance of a parallel plate capacitor with air as medium is 6 μ F. With the introduction of a dielectric medium, the capacitance becomes 30 μ F. The permittivity of the medium is: (ϵ0 = 8.85 × 10-12 C2N-1m-2)

Question

The capacitance of a parallel plate capacitor with air as medium is 6 μ F. With the introduction of a dielectric medium, the capacitance becomes 30 μ F. The permittivity of the medium is: (ϵ0 = 8.85 × 10-12 C2N-1m-2) (A) 0.44 × 10-13 C2 N-1m-2 (B) 1.77 × 10-12 C2 N-1m-2 (C) 0.44 × 10-10 C2 N-1m-2 (D) 5.00 C2 N-1m-2

Tardigrade Admin · Accepted Answer

C=KC0 K=(C/C0) =(30/6)=5 K=(ε/ε0) ε=K ε0 =5 × 8.85× 10-12 =0.44 × 10-10 C2 N-1 m-2

Q. The capacitance of a parallel plate capacitor with air as medium is $6 μ F$ . With the introduction of a dielectric medium, the capacitance becomes 30 $μ F .$ The permittivity of the medium is :
$(ϵ_{0} = 8.85 \times 1 0^{- 12} C^{2} N^{- 1} m^{- 2}$ )

$0.44 \times 1 0^{- 13} C^{2} N^{- 1} m^{- 2}$

$1.77 \times 1 0^{- 12} C^{2} N^{- 1} m^{- 2}$

$0.44 \times 1 0^{- 10} C^{2} N^{- 1} m^{- 2}$

$5.00 C^{2} N^{- 1} m^{- 2}$

$C = K C_{0}$
$K = \frac{C}{C _{0}}$
$= \frac{30}{6} = 5$
$K = \frac{ε}{ε _{0}}$
$ε = K ε_{0}$
$= 5 \times 8.85 \times 1 0^{- 12}$
$= 0.44 \times 1 0^{- 10} C^{2} N^{- 1} m^{- 2}$

Q. The capacitance of a parallel plate capacitor with air as medium is 6μF. With the introduction of a dielectric medium, the capacitance becomes 30 μF. The permittivity of the medium is : (ϵ0​=8.85×10−12C2N−1m−2)

0.44×10−13C2N−1m−2

1.77×10−12C2N−1m−2

0.44×10−10C2N−1m−2

5.00C2N−1m−2