The calculated spin only magnetic moments of [ Cr ( NH 3)6]3+ and [ CuF 6]3- in BM, respectively, are (Atomic number of Cr and Cu are 24 and 29 , respectively)

Question

The calculated spin only magnetic moments of [ Cr ( NH 3)6]3+ and [ CuF 6]3- in BM, respectively, are (Atomic number of Cr and Cu are 24 and 29 , respectively) (A) 3.87 and 2.84 (B) 4.90 and 1.73 (C) 3.87 and 1.73 (D) 4.90 and 2.84

Tardigrade Admin · Accepted Answer

[ Cr ( NH 3)6]3+ has d 3 configuration, so as per CFT, N =3 and μ=√3(3+2)=3.87 BM [ CuF 6]3-, has d 8 configuration and weak field ligand. So N =2 and μ=√2(2+2)=2.84 BM

Q. The calculated spin only magnetic moments of $[C r (N H_{3})_{6}]^{3 +}$ and $[C u F_{6}]^{3 -}$ in BM, respectively, are (Atomic number of $C r$ and $C u$ are $24$ and $29$ , respectively)

3.87 and 2.84

4.90 and 1.73

3.87 and 1.73

4.90 and 2.84

$[C r (N H_{3})_{6}]^{3 +}$ has $d^{3}$ configuration, so as per $CFT$ ,
$N = 3$ and $μ = 3 (3 + 2) = 3.87 BM$
$[C u F_{6}]^{3 -}$ , has $d^{8}$ configuration and weak field ligand.
So $N = 2$ and $μ = 2 (2 + 2) = 2.84 BM$

Q. The calculated spin only magnetic moments of [Cr(NH3​)6​]3+ and [CuF6​]3− in BM, respectively, are (Atomic number of Cr and Cu are 24 and 29 , respectively)